11/2/2022 0 Comments Brake caliper diagram![]() Put in the actual numbers, not (for example) F = ma for the deceleration force. You will have to decide if simple is good enough, or if you need to be correct. Assuming that tire normal force is the same at both constant speed and heavy braking simplifies the calculations, but is not correct. The total braking force, of course, is equal to ma. This will be the actual braking force in a properly balanced brake system, or a brake system with a working antilock system. The maximum braking force of each tire is proportional to the tire normal force. #BRAKE CALIPER DIAGRAM PATCH#If you take a sum of moments about either tire contact patch in the whole car FBD, you will find that the tire normal force is not 210/160 kg. #BRAKE CALIPER DIAGRAM DRIVER#If the wheel locks up, then you will have extra internal forces acting on your caliper (but not at the tire) if the driver pushes harder on the pedal (your first equation, without the #\frac\times 2 \times coef\ of\ friction#). In any circumstance, as long as the wheels turn, the maximum force will be dictated by the tire friction force (your second equation). The logical conclusion from looking at those results is that the braking system requires less brake pedal force to achieve the desired tire performance.
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